Henry and Jenson had 96 markers together. Henry had 14 more markers than Jenson. Both of them sold some of their markers. Jenson sold 20% less markers than what Henry sold. In the end, Jenson had half as many markers left as Henry. How many markers had Henry left?
| |
Henry
(1) |
Jenson
(2) |
Make p the same
(2)x2 = (3) |
Comparing Henry
and Jenson at first |
14 more |
|
|
| Before |
55 |
41 |
82 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Jenson had at first
= (96 - 14) ÷ 2
= 82 ÷ 2
= 41
Number of markers that Henry had at first
= 41 + 14
= 55
Number of markers that Jenson sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
55 - 5 u = 82 - 8 u
8 u - 5 u = 82 - 55
3 u = 27
1 u = 27 ÷ 3 = 9
Number of markers that Henry had left
= 55 - 5 u
= 55 - 5 x 9
= 55 - 45
= 10
Answer(s): 10
