Julian and Ivan had 182 pencils together. Julian had 34 more pencils than Ivan. Both of them sold some of their pencils. Ivan sold 30% less pencils than what Julian sold. In the end, Ivan had half as many pencils left as Julian. How many pencils had Julian left?
| |
Julian
(1) |
Ivan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Julian
and Ivan at first |
34 more |
|
|
| Before |
108 |
74 |
148 |
| Change |
- 10 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Ivan had at first
= (182 - 34) ÷ 2
= 148 ÷ 2
= 74
Number of pencils that Julian had at first
= 74 + 34
= 108
Number of pencils that Ivan sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
108 - 10 u = 148 - 14 u
14 u - 10 u = 148 - 108
4 u = 40
1 u = 40 ÷ 4 = 10
Number of pencils that Julian had left
= 108 - 10 u
= 108 - 10 x 10
= 108 - 100
= 8
Answer(s): 8
