Charlie and George had 95 pencils together. Charlie had 25 more pencils than George. Both of them sold some of their pencils. George sold 40% less pencils than what Charlie sold. In the end, George had half as many pencils left as Charlie. How many pencils had Charlie left?
| |
Charlie
(1) |
George
(2) |
Make p the same
(2)x2 = (3) |
Comparing Charlie
and George at first |
25 more |
|
|
| Before |
60 |
35 |
70 |
| Change |
- 5 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that George had at first
= (95 - 25) ÷ 2
= 70 ÷ 2
= 35
Number of pencils that Charlie had at first
= 35 + 25
= 60
Number of pencils that George sold in percent
= 100% - 40%
= 60%
60% =
60100 =
35 Make p the same.
(1) = (3)
60 - 5 u = 70 - 6 u
6 u - 5 u = 70 - 60
1 u = 10
1 u = 10 ÷ 1 = 10
Number of pencils that Charlie had left
= 60 - 5 u
= 60 - 5 x 10
= 60 - 50
= 10
Answer(s): 10
