Albert and Gabriel had 51 staplers together. Albert had 11 more staplers than Gabriel. Both of them sold some of their staplers. Gabriel sold 20% less staplers than what Albert sold. In the end, Gabriel had half as many staplers left as Albert. How many staplers had Albert left?
|
Albert (1) |
Gabriel (2) |
Make p the same (2)x2 = (3) |
Comparing Albert and Gabriel at first |
11 more |
|
|
Before |
31 |
20 |
40 |
Change |
- 5 u |
- 4 u |
- 8 u |
After |
2 p |
1 p |
2 p |
Number of staplers that Gabriel had at first
= (51 - 11) ÷ 2
= 40 ÷ 2
= 20
Number of staplers that Albert had at first
= 20 + 11
= 31
Number of staplers that Gabriel sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
31 - 5 u = 40 - 8 u
8 u - 5 u = 40 - 31
3 u = 9
1 u = 9 ÷ 3 = 3
Number of staplers that Albert had left
= 31 - 5 u
= 31 - 5 x 3
= 31 - 15
= 16
Answer(s): 16