Will and Bryan had 93 markers together. Will had 15 more markers than Bryan. Both of them sold some of their markers. Bryan sold 25% less markers than what Will sold. In the end, Bryan had half as many markers left as Will. How many markers had Will left?
| |
Will
(1) |
Bryan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Will
and Bryan at first |
15 more |
|
|
| Before |
54 |
39 |
78 |
| Change |
- 4 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Bryan had at first
= (93 - 15) ÷ 2
= 78 ÷ 2
= 39
Number of markers that Will had at first
= 39 + 15
= 54
Number of markers that Bryan sold in percent
= 100% - 25%
= 75%
75% =
75100 =
34 Make p the same.
(1) = (3)
54 - 4 u = 78 - 6 u
6 u - 4 u = 78 - 54
2 u = 24
1 u = 24 ÷ 2 = 12
Number of markers that Will had left
= 54 - 4 u
= 54 - 4 x 12
= 54 - 48
= 6
Answer(s): 6
