Glen and Cody had 246 notebooks together. Cody had 2 less notebooks than Glen. Both of them sold some of their notebooks. Cody sold 10% more notebooks than what Glen sold. In the end, Cody had half as many notebooks left as Glen. How many notebooks had Cody left?
|
Glen (1) |
Cody (2) |
Make p the same (2)x2 = (3) |
Comparing Glen and Cody at first |
2 more |
|
|
Before |
124 |
122 |
244 |
Change |
- 10 u |
- 11 u |
- 22 u |
After |
2 p |
1 p |
2 p |
Number of notebooks that Cody had at first
= (246 - 2) ÷ 2
= 244 ÷ 2
= 122
Number of notebooks that Glen had at first
= 122 + 2
= 124
Number of notebooks that Cody sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
124 - 10 u = 244 - 22 u
22 u - 10 u = 244 - 124
12 u = 120
1 u = 120 ÷ 12 = 10
Number of notebooks that Cody had left
= 122 - 11 u
= 122 - 11 x 10
= 122 - 110
= 12
Answer(s): 12