Paul and Oscar had 46 pens together. Paul had 10 more pens than Oscar. Both of them sold some of their pens. Oscar sold 25% less pens than what Paul sold. In the end, Oscar had half as many pens left as Paul. How many pens had Paul left?
| |
Paul
(1) |
Oscar
(2) |
Make p the same
(2)x2 = (3) |
Comparing Paul
and Oscar at first |
10 more |
|
|
| Before |
28 |
18 |
36 |
| Change |
- 4 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Oscar had at first
= (46 - 10) ÷ 2
= 36 ÷ 2
= 18
Number of pens that Paul had at first
= 18 + 10
= 28
Number of pens that Oscar sold in percent
= 100% - 25%
= 75%
75% =
75100 =
34 Make p the same.
(1) = (3)
28 - 4 u = 36 - 6 u
6 u - 4 u = 36 - 28
2 u = 8
1 u = 8 ÷ 2 = 4
Number of pens that Paul had left
= 28 - 4 u
= 28 - 4 x 4
= 28 - 16
= 12
Answer(s): 12
