Sean and Liam had 70 notebooks together. Liam had 2 less notebooks than Sean. Both of them sold some of their notebooks. Liam sold 30% more notebooks than what Sean sold. In the end, Liam had half as many notebooks left as Sean. How many notebooks had Liam left?
| |
Sean
(1) |
Liam
(2) |
Make p the same
(2)x2 = (3) |
Comparing Sean
and Liam at first |
2 more |
|
|
| Before |
36 |
34 |
68 |
| Change |
- 10 u |
- 13 u |
- 26 u |
| After |
2 p |
1 p |
2 p |
Number of notebooks that Liam had at first
= (70 - 2) ÷ 2
= 68 ÷ 2
= 34
Number of notebooks that Sean had at first
= 34 + 2
= 36
Number of notebooks that Liam sold in percent
= 100% + 30%
= 130%
130% =
130100 =
1310 Make p the same.
(1) = (3)
36 - 10 u = 68 - 26 u
26 u - 10 u = 68 - 36
16 u = 32
1 u = 32 ÷ 16 = 2
Number of notebooks that Liam had left
= 34 - 13 u
= 34 - 13 x 2
= 34 - 26
= 8
Answer(s): 8
