Asher and Jack had 224 pens together. Asher had 16 more pens than Jack. Both of them sold some of their pens. Jack sold 10% less pens than what Asher sold. In the end, Jack had half as many pens left as Asher. How many pens had Asher left?
|
Asher (1) |
Jack (2) |
Make p the same (2)x2 = (3) |
Comparing Asher and Jack at first |
16 more |
|
|
Before |
120 |
104 |
208 |
Change |
- 10 u |
- 9 u |
- 18 u |
After |
2 p |
1 p |
2 p |
Number of pens that Jack had at first
= (224 - 16) ÷ 2
= 208 ÷ 2
= 104
Number of pens that Asher had at first
= 104 + 16
= 120
Number of pens that Jack sold in percent
= 100% - 10%
= 90%
90% =
90100 =
910 Make p the same.
(1) = (3)
120 - 10 u = 208 - 18 u
18 u - 10 u = 208 - 120
8 u = 88
1 u = 88 ÷ 8 = 11
Number of pens that Asher had left
= 120 - 10 u
= 120 - 10 x 11
= 120 - 110
= 10
Answer(s): 10