George and Fred had 99 markers together. Fred had 5 less markers than George. Both of them sold some of their markers. Fred sold 25% more markers than what George sold. In the end, Fred had half as many markers left as George. How many markers had Fred left?
| |
George
(1) |
Fred
(2) |
Make p the same
(2)x2 = (3) |
Comparing George
and Fred at first |
5 more |
|
|
| Before |
52 |
47 |
94 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Fred had at first
= (99 - 5) ÷ 2
= 94 ÷ 2
= 47
Number of markers that George had at first
= 47 + 5
= 52
Number of markers that Fred sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
52 - 4 u = 94 - 10 u
10 u - 4 u = 94 - 52
6 u = 42
1 u = 42 ÷ 6 = 7
Number of markers that Fred had left
= 47 - 5 u
= 47 - 5 x 7
= 47 - 35
= 12
Answer(s): 12
