Henry and Oscar had 84 markers together. Oscar had 4 less markers than Henry. Both of them sold some of their markers. Oscar sold 40% more markers than what Henry sold. In the end, Oscar had half as many markers left as Henry. How many markers had Oscar left?
| |
Henry
(1) |
Oscar
(2) |
Make p the same
(2)x2 = (3) |
Comparing Henry
and Oscar at first |
4 more |
|
|
| Before |
44 |
40 |
80 |
| Change |
- 5 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Oscar had at first
= (84 - 4) ÷ 2
= 80 ÷ 2
= 40
Number of markers that Henry had at first
= 40 + 4
= 44
Number of markers that Oscar sold in percent
= 100% + 40%
= 140%
140% =
140100 =
75 Make p the same.
(1) = (3)
44 - 5 u = 80 - 14 u
14 u - 5 u = 80 - 44
9 u = 36
1 u = 36 ÷ 9 = 4
Number of markers that Oscar had left
= 40 - 7 u
= 40 - 7 x 4
= 40 - 28
= 12
Answer(s): 12
