Lee and Oliver had 111 markers together. Oliver had 5 less markers than Lee. Both of them sold some of their markers. Oliver sold 10% more markers than what Lee sold. In the end, Oliver had half as many markers left as Lee. How many markers had Oliver left?
| |
Lee
(1) |
Oliver
(2) |
Make p the same
(2)x2 = (3) |
Comparing Lee
and Oliver at first |
5 more |
|
|
| Before |
58 |
53 |
106 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Oliver had at first
= (111 - 5) ÷ 2
= 106 ÷ 2
= 53
Number of markers that Lee had at first
= 53 + 5
= 58
Number of markers that Oliver sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
58 - 10 u = 106 - 22 u
22 u - 10 u = 106 - 58
12 u = 48
1 u = 48 ÷ 12 = 4
Number of markers that Oliver had left
= 53 - 11 u
= 53 - 11 x 4
= 53 - 44
= 9
Answer(s): 9
