Will and Xavier had 33 notebooks together. Xavier had 3 less notebooks than Will. Both of them sold some of their notebooks. Xavier sold 25% more notebooks than what Will sold. In the end, Xavier had half as many notebooks left as Will. How many notebooks had Xavier left?
| |
Will
(1) |
Xavier
(2) |
Make p the same
(2)x2 = (3) |
Comparing Will
and Xavier at first |
3 more |
|
|
| Before |
18 |
15 |
30 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of notebooks that Xavier had at first
= (33 - 3) ÷ 2
= 30 ÷ 2
= 15
Number of notebooks that Will had at first
= 15 + 3
= 18
Number of notebooks that Xavier sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
18 - 4 u = 30 - 10 u
10 u - 4 u = 30 - 18
6 u = 12
1 u = 12 ÷ 6 = 2
Number of notebooks that Xavier had left
= 15 - 5 u
= 15 - 5 x 2
= 15 - 10
= 5
Answer(s): 5
