Valen and Howard had 57 pens together. Howard had 3 less pens than Valen. Both of them sold some of their pens. Howard sold 10% more pens than what Valen sold. In the end, Howard had half as many pens left as Valen. How many pens had Howard left?
| |
Valen
(1) |
Howard
(2) |
Make p the same
(2)x2 = (3) |
Comparing Valen
and Howard at first |
3 more |
|
|
| Before |
30 |
27 |
54 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Howard had at first
= (57 - 3) ÷ 2
= 54 ÷ 2
= 27
Number of pens that Valen had at first
= 27 + 3
= 30
Number of pens that Howard sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
30 - 10 u = 54 - 22 u
22 u - 10 u = 54 - 30
12 u = 24
1 u = 24 ÷ 12 = 2
Number of pens that Howard had left
= 27 - 11 u
= 27 - 11 x 2
= 27 - 22
= 5
Answer(s): 5
