Jeremy and Valen had 66 pens together. Jeremy had 10 more pens than Valen. Both of them sold some of their pens. Valen sold 20% less pens than what Jeremy sold. In the end, Valen had half as many pens left as Jeremy. How many pens had Jeremy left?
| |
Jeremy
(1) |
Valen
(2) |
Make p the same
(2)x2 = (3) |
Comparing Jeremy
and Valen at first |
10 more |
|
|
| Before |
38 |
28 |
56 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Valen had at first
= (66 - 10) ÷ 2
= 56 ÷ 2
= 28
Number of pens that Jeremy had at first
= 28 + 10
= 38
Number of pens that Valen sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
38 - 5 u = 56 - 8 u
8 u - 5 u = 56 - 38
3 u = 18
1 u = 18 ÷ 3 = 6
Number of pens that Jeremy had left
= 38 - 5 u
= 38 - 5 x 6
= 38 - 30
= 8
Answer(s): 8
