Vaidev and Neave had 120 markers together. Neave had 8 less markers than Vaidev. Both of them sold some of their markers. Neave sold 10% more markers than what Vaidev sold. In the end, Neave had half as many markers left as Vaidev. How many markers had Neave left?
| |
Vaidev
(1) |
Neave
(2) |
Make p the same
(2)x2 = (3) |
Comparing Vaidev
and Neave at first |
8 more |
|
|
| Before |
64 |
56 |
112 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Neave had at first
= (120 - 8) ÷ 2
= 112 ÷ 2
= 56
Number of markers that Vaidev had at first
= 56 + 8
= 64
Number of markers that Neave sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
64 - 10 u = 112 - 22 u
22 u - 10 u = 112 - 64
12 u = 48
1 u = 48 ÷ 12 = 4
Number of markers that Neave had left
= 56 - 11 u
= 56 - 11 x 4
= 56 - 44
= 12
Answer(s): 12
