Jenson and Bryan had 96 pens together. Jenson had 12 more pens than Bryan. Both of them sold some of their pens. Bryan sold 20% less pens than what Jenson sold. In the end, Bryan had half as many pens left as Jenson. How many pens had Jenson left?
| |
Jenson
(1) |
Bryan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Jenson
and Bryan at first |
12 more |
|
|
| Before |
54 |
42 |
84 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Bryan had at first
= (96 - 12) ÷ 2
= 84 ÷ 2
= 42
Number of pens that Jenson had at first
= 42 + 12
= 54
Number of pens that Bryan sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
54 - 5 u = 84 - 8 u
8 u - 5 u = 84 - 54
3 u = 30
1 u = 30 ÷ 3 = 10
Number of pens that Jenson had left
= 54 - 5 u
= 54 - 5 x 10
= 54 - 50
= 4
Answer(s): 4
