Billy and Luis had 42 markers together. Billy had 10 more markers than Luis. Both of them sold some of their markers. Luis sold 25% less markers than what Billy sold. In the end, Luis had half as many markers left as Billy. How many markers had Billy left?
| |
Billy
(1) |
Luis
(2) |
Make p the same
(2)x2 = (3) |
Comparing Billy
and Luis at first |
10 more |
|
|
| Before |
26 |
16 |
32 |
| Change |
- 4 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Luis had at first
= (42 - 10) ÷ 2
= 32 ÷ 2
= 16
Number of markers that Billy had at first
= 16 + 10
= 26
Number of markers that Luis sold in percent
= 100% - 25%
= 75%
75% =
75100 =
34 Make p the same.
(1) = (3)
26 - 4 u = 32 - 6 u
6 u - 4 u = 32 - 26
2 u = 6
1 u = 6 ÷ 2 = 3
Number of markers that Billy had left
= 26 - 4 u
= 26 - 4 x 3
= 26 - 12
= 14
Answer(s): 14
