Ethan and Riordan had 135 markers together. Riordan had 5 less markers than Ethan. Both of them sold some of their markers. Riordan sold 10% more markers than what Ethan sold. In the end, Riordan had half as many markers left as Ethan. How many markers had Riordan left?
| |
Ethan
(1) |
Riordan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Ethan
and Riordan at first |
5 more |
|
|
| Before |
70 |
65 |
130 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Riordan had at first
= (135 - 5) ÷ 2
= 130 ÷ 2
= 65
Number of markers that Ethan had at first
= 65 + 5
= 70
Number of markers that Riordan sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
70 - 10 u = 130 - 22 u
22 u - 10 u = 130 - 70
12 u = 60
1 u = 60 ÷ 12 = 5
Number of markers that Riordan had left
= 65 - 11 u
= 65 - 11 x 5
= 65 - 55
= 10
Answer(s): 10
