Peter and Jeremy had 63 markers together. Jeremy had 7 less markers than Peter. Both of them sold some of their markers. Jeremy sold 20% more markers than what Peter sold. In the end, Jeremy had half as many markers left as Peter. How many markers had Jeremy left?
| |
Peter
(1) |
Jeremy
(2) |
Make p the same
(2)x2 = (3) |
Comparing Peter
and Jeremy at first |
7 more |
|
|
| Before |
35 |
28 |
56 |
| Change |
- 5 u |
- 6 u |
- 12 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Jeremy had at first
= (63 - 7) ÷ 2
= 56 ÷ 2
= 28
Number of markers that Peter had at first
= 28 + 7
= 35
Number of markers that Jeremy sold in percent
= 100% + 20%
= 120%
120% =
120100 =
65 Make p the same.
(1) = (3)
35 - 5 u = 56 - 12 u
12 u - 5 u = 56 - 35
7 u = 21
1 u = 21 ÷ 7 = 3
Number of markers that Jeremy had left
= 28 - 6 u
= 28 - 6 x 3
= 28 - 18
= 10
Answer(s): 10
