Bryan and Will had 105 pens together. Will had 3 less pens than Bryan. Both of them sold some of their pens. Will sold 10% more pens than what Bryan sold. In the end, Will had half as many pens left as Bryan. How many pens had Will left?
| |
Bryan
(1) |
Will
(2) |
Make p the same
(2)x2 = (3) |
Comparing Bryan
and Will at first |
3 more |
|
|
| Before |
54 |
51 |
102 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Will had at first
= (105 - 3) ÷ 2
= 102 ÷ 2
= 51
Number of pens that Bryan had at first
= 51 + 3
= 54
Number of pens that Will sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
54 - 10 u = 102 - 22 u
22 u - 10 u = 102 - 54
12 u = 48
1 u = 48 ÷ 12 = 4
Number of pens that Will had left
= 51 - 11 u
= 51 - 11 x 4
= 51 - 44
= 7
Answer(s): 7
