Pierre and Ivan had 125 staplers together. Pierre had 23 more staplers than Ivan. Both of them sold some of their staplers. Ivan sold 30% less staplers than what Pierre sold. In the end, Ivan had half as many staplers left as Pierre. How many staplers had Pierre left?
| |
Pierre
(1) |
Ivan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Pierre
and Ivan at first |
23 more |
|
|
| Before |
74 |
51 |
102 |
| Change |
- 10 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of staplers that Ivan had at first
= (125 - 23) ÷ 2
= 102 ÷ 2
= 51
Number of staplers that Pierre had at first
= 51 + 23
= 74
Number of staplers that Ivan sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
74 - 10 u = 102 - 14 u
14 u - 10 u = 102 - 74
4 u = 28
1 u = 28 ÷ 4 = 7
Number of staplers that Pierre had left
= 74 - 10 u
= 74 - 10 x 7
= 74 - 70
= 4
Answer(s): 4
