Jack and Xavier had 57 markers together. Xavier had 3 less markers than Jack. Both of them sold some of their markers. Xavier sold 25% more markers than what Jack sold. In the end, Xavier had half as many markers left as Jack. How many markers had Xavier left?
| |
Jack
(1) |
Xavier
(2) |
Make p the same
(2)x2 = (3) |
Comparing Jack
and Xavier at first |
3 more |
|
|
| Before |
30 |
27 |
54 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Xavier had at first
= (57 - 3) ÷ 2
= 54 ÷ 2
= 27
Number of markers that Jack had at first
= 27 + 3
= 30
Number of markers that Xavier sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
30 - 4 u = 54 - 10 u
10 u - 4 u = 54 - 30
6 u = 24
1 u = 24 ÷ 6 = 4
Number of markers that Xavier had left
= 27 - 5 u
= 27 - 5 x 4
= 27 - 20
= 7
Answer(s): 7
