Owen and Simon had 102 pencils together. Owen had 16 more pencils than Simon. Both of them sold some of their pencils. Simon sold 20% less pencils than what Owen sold. In the end, Simon had half as many pencils left as Owen. How many pencils had Owen left?
| |
Owen
(1) |
Simon
(2) |
Make p the same
(2)x2 = (3) |
Comparing Owen
and Simon at first |
16 more |
|
|
| Before |
59 |
43 |
86 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Simon had at first
= (102 - 16) ÷ 2
= 86 ÷ 2
= 43
Number of pencils that Owen had at first
= 43 + 16
= 59
Number of pencils that Simon sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
59 - 5 u = 86 - 8 u
8 u - 5 u = 86 - 59
3 u = 27
1 u = 27 ÷ 3 = 9
Number of pencils that Owen had left
= 59 - 5 u
= 59 - 5 x 9
= 59 - 45
= 14
Answer(s): 14
