Perry and Ivan had 54 markers together. Ivan had 2 less markers than Perry. Both of them sold some of their markers. Ivan sold 10% more markers than what Perry sold. In the end, Ivan had half as many markers left as Perry. How many markers had Ivan left?
| |
Perry
(1) |
Ivan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Perry
and Ivan at first |
2 more |
|
|
| Before |
28 |
26 |
52 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Ivan had at first
= (54 - 2) ÷ 2
= 52 ÷ 2
= 26
Number of markers that Perry had at first
= 26 + 2
= 28
Number of markers that Ivan sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
28 - 10 u = 52 - 22 u
22 u - 10 u = 52 - 28
12 u = 24
1 u = 24 ÷ 12 = 2
Number of markers that Ivan had left
= 26 - 11 u
= 26 - 11 x 2
= 26 - 22
= 4
Answer(s): 4
