Michael and Tim had 66 pens together. Tim had 6 less pens than Michael. Both of them sold some of their pens. Tim sold 10% more pens than what Michael sold. In the end, Tim had half as many pens left as Michael. How many pens had Tim left?
| |
Michael
(1) |
Tim
(2) |
Make p the same
(2)x2 = (3) |
Comparing Michael
and Tim at first |
6 more |
|
|
| Before |
36 |
30 |
60 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Tim had at first
= (66 - 6) ÷ 2
= 60 ÷ 2
= 30
Number of pens that Michael had at first
= 30 + 6
= 36
Number of pens that Tim sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
36 - 10 u = 60 - 22 u
22 u - 10 u = 60 - 36
12 u = 24
1 u = 24 ÷ 12 = 2
Number of pens that Tim had left
= 30 - 11 u
= 30 - 11 x 2
= 30 - 22
= 8
Answer(s): 8
