Eric and Cody had 60 markers together. Eric had 12 more markers than Cody. Both of them sold some of their markers. Cody sold 20% less markers than what Eric sold. In the end, Cody had half as many markers left as Eric. How many markers had Eric left?
| |
Eric
(1) |
Cody
(2) |
Make p the same
(2)x2 = (3) |
Comparing Eric
and Cody at first |
12 more |
|
|
| Before |
36 |
24 |
48 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Cody had at first
= (60 - 12) ÷ 2
= 48 ÷ 2
= 24
Number of markers that Eric had at first
= 24 + 12
= 36
Number of markers that Cody sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
36 - 5 u = 48 - 8 u
8 u - 5 u = 48 - 36
3 u = 12
1 u = 12 ÷ 3 = 4
Number of markers that Eric had left
= 36 - 5 u
= 36 - 5 x 4
= 36 - 20
= 16
Answer(s): 16
