Liam and Japheth had 65 pens together. Japheth had 3 less pens than Liam. Both of them sold some of their pens. Japheth sold 20% more pens than what Liam sold. In the end, Japheth had half as many pens left as Liam. How many pens had Japheth left?
| |
Liam
(1) |
Japheth
(2) |
Make p the same
(2)x2 = (3) |
Comparing Liam
and Japheth at first |
3 more |
|
|
| Before |
34 |
31 |
62 |
| Change |
- 5 u |
- 6 u |
- 12 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Japheth had at first
= (65 - 3) ÷ 2
= 62 ÷ 2
= 31
Number of pens that Liam had at first
= 31 + 3
= 34
Number of pens that Japheth sold in percent
= 100% + 20%
= 120%
120% =
120100 =
65 Make p the same.
(1) = (3)
34 - 5 u = 62 - 12 u
12 u - 5 u = 62 - 34
7 u = 28
1 u = 28 ÷ 7 = 4
Number of pens that Japheth had left
= 31 - 6 u
= 31 - 6 x 4
= 31 - 24
= 7
Answer(s): 7
