Simon and Ben had 165 markers together. Simon had 31 more markers than Ben. Both of them sold some of their markers. Ben sold 30% less markers than what Simon sold. In the end, Ben had half as many markers left as Simon. How many markers had Simon left?
| |
Simon
(1) |
Ben
(2) |
Make p the same
(2)x2 = (3) |
Comparing Simon
and Ben at first |
31 more |
|
|
| Before |
98 |
67 |
134 |
| Change |
- 10 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Ben had at first
= (165 - 31) ÷ 2
= 134 ÷ 2
= 67
Number of markers that Simon had at first
= 67 + 31
= 98
Number of markers that Ben sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
98 - 10 u = 134 - 14 u
14 u - 10 u = 134 - 98
4 u = 36
1 u = 36 ÷ 4 = 9
Number of markers that Simon had left
= 98 - 10 u
= 98 - 10 x 9
= 98 - 90
= 8
Answer(s): 8
