Fabian and Neave had 166 pens together. Fabian had 18 more pens than Neave. Both of them sold some of their pens. Neave sold 10% less pens than what Fabian sold. In the end, Neave had half as many pens left as Fabian. How many pens had Fabian left?
| |
Fabian
(1) |
Neave
(2) |
Make p the same
(2)x2 = (3) |
Comparing Fabian
and Neave at first |
18 more |
|
|
| Before |
92 |
74 |
148 |
| Change |
- 10 u |
- 9 u |
- 18 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Neave had at first
= (166 - 18) ÷ 2
= 148 ÷ 2
= 74
Number of pens that Fabian had at first
= 74 + 18
= 92
Number of pens that Neave sold in percent
= 100% - 10%
= 90%
90% =
90100 =
910 Make p the same.
(1) = (3)
92 - 10 u = 148 - 18 u
18 u - 10 u = 148 - 92
8 u = 56
1 u = 56 ÷ 8 = 7
Number of pens that Fabian had left
= 92 - 10 u
= 92 - 10 x 7
= 92 - 70
= 22
Answer(s): 22
