Ben and Reggie had 177 pencils together. Reggie had 3 less pencils than Ben. Both of them sold some of their pencils. Reggie sold 10% more pencils than what Ben sold. In the end, Reggie had half as many pencils left as Ben. How many pencils had Reggie left?
| |
Ben
(1) |
Reggie
(2) |
Make p the same
(2)x2 = (3) |
Comparing Ben
and Reggie at first |
3 more |
|
|
| Before |
90 |
87 |
174 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Reggie had at first
= (177 - 3) ÷ 2
= 174 ÷ 2
= 87
Number of pencils that Ben had at first
= 87 + 3
= 90
Number of pencils that Reggie sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
90 - 10 u = 174 - 22 u
22 u - 10 u = 174 - 90
12 u = 84
1 u = 84 ÷ 12 = 7
Number of pencils that Reggie had left
= 87 - 11 u
= 87 - 11 x 7
= 87 - 77
= 10
Answer(s): 10
