Rael and Will had 69 markers together. Will had 5 less markers than Rael. Both of them sold some of their markers. Will sold 40% more markers than what Rael sold. In the end, Will had half as many markers left as Rael. How many markers had Will left?
| |
Rael
(1) |
Will
(2) |
Make p the same
(2)x2 = (3) |
Comparing Rael
and Will at first |
5 more |
|
|
| Before |
37 |
32 |
64 |
| Change |
- 5 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Will had at first
= (69 - 5) ÷ 2
= 64 ÷ 2
= 32
Number of markers that Rael had at first
= 32 + 5
= 37
Number of markers that Will sold in percent
= 100% + 40%
= 140%
140% =
140100 =
75 Make p the same.
(1) = (3)
37 - 5 u = 64 - 14 u
14 u - 5 u = 64 - 37
9 u = 27
1 u = 27 ÷ 9 = 3
Number of markers that Will had left
= 32 - 7 u
= 32 - 7 x 3
= 32 - 21
= 11
Answer(s): 11
