Mr Lee bought some pizzas for a group of children. There was an equal number of girls and boys. The girls received 2 times as many pizzas as the boys. Each boy ate
16 of a pizza and the boys finished all the pizzas given to them. Each girl ate
118 of a pizza and the girls had 5
59 pizzas left. How many pizzas did Mr Lee buy?
|
Girls (1) |
Boys (2) |
Before |
2 u |
1 u |
Change |
- 1 p |
- 3 p |
After |
100 |
0 |
16 =
318 Cutting the slices of pizzas into same size. Each pizza was cut into 18 slices. Every girl ate 1 slice of pizza and every boy ate 3 slices of pizza.
Number of slices that the girls had left
= 5
59 ÷
118 =
509 x 18
= 100
2 u - 1 p = 100 --- (1)
1 u - 3 p = 0
1 u = 3 p --- (2)
Make u the same.
(2)
x22 u = 6 p --- (3)
Substitute (3) into (1).
2 u - 1 p = 100
6 p - 1 p = 100
5 p = 100
1 p = 100 ÷ 5 = 20
Total number of slices of pizzas for girls
= 100 + 1 p
= 100 + 20
= 120
Total number of slices of pizzas for boys
= 120 ÷ 2
= 60
Total number of slices of pizzas for children
= 120 + 60
= 180
Total number of pizzas that Mr Lee bought
= 180 ÷ 18
= 10
Answer(s): 10