Mr Dylan bought some pizzas for a group of children. There was an equal number of boys and girls. The boys received 4 times as many pizzas as the girls. Each girl ate
13 of a pizza and the girls finished all the pizzas given to them. Each boy ate
19 of a pizza and the boys had 14
23 pizzas left. How many pizzas did Mr Dylan buy?
|
Boys (1) |
Girls (2) |
Before |
4 u |
1 u |
Change |
- 1 p |
- 3 p |
After |
132 |
0 |
13 =
39 Cutting the slices of pizzas into same size. Each pizza was cut into 9 slices. Every boy ate 1 slice of pizza and every girl ate 3 slices of pizza.
Number of slices that the boys had left
= 14
23 ÷
19 =
443 x 9
= 132
4 u - 1 p = 132 --- (1)
1 u - 3 p = 0
1 u = 3 p --- (2)
Make u the same.
(2)
x44 u = 12 p --- (3)
Substitute (3) into (1).
4 u - 1 p = 132
12 p - 1 p = 132
11 p = 132
1 p = 132 ÷ 11 = 12
Total number of slices of pizzas for boys
= 132 + 1 p
= 132 + 12
= 144
Total number of slices of pizzas for girls
= 144 ÷ 4
= 36
Total number of slices of pizzas for children
= 144 + 36
= 180
Total number of pizzas that Mr Dylan bought
= 180 ÷ 9
= 20
Answer(s): 20