Abi has 3 times as many coins as Marion. Marion has
27 as many coins as Cindy. If the three of them have a total of 120 coins, how many coins does Cindy have?
Abi |
Marion |
Cindy |
3x2 |
1x2 |
|
|
2x1 |
7x1 |
6 u |
2 u |
7 u |
The number of coins that Marion has is repeated. Make the number of coins that Marion has the same. LCM of 1 and 2 is 2.
Total number of coins that the three of them have
= 6 u + 2 u + 7 u
= 15 u
15 u = 120
1 u = 120 ÷ 15 = 8
Number of coins that Cindy has
= 7 u
= 7 x 8
= 56
Answer(s): 56