Jane has 2 times as many coins as Lucy. Lucy has
25 as many coins as Erika. If the three of them have a total of 33 coins, how many coins does Jane have?
Jane |
Lucy |
Erika |
2x2 |
1x2 |
|
|
2x1 |
5x1 |
4 u |
2 u |
5 u |
The number of coins that Lucy has is repeated. Make the number of coins that Lucy has the same. LCM of 1 and 2 is 2.
Total number of coins that the three of them have
= 4 u + 2 u + 5 u
= 11 u
11 u = 33
1 u = 33 ÷ 11 = 3
Number of coins that Jane has
= 4 u
= 4 x 3
= 12
Answer(s): 12