Tina has 2 times as many coins as Joelle. Joelle has
45 as many coins as Xuan. If the three of them have a total of 51 coins, how many coins does Tina have?
Tina |
Joelle |
Xuan |
2x4 |
1x4 |
|
|
4x1 |
5x1 |
8 u |
4 u |
5 u |
The number of coins that Joelle has is repeated. Make the number of coins that Joelle has the same. LCM of 1 and 4 is 4.
Total number of coins that the three of them have
= 8 u + 4 u + 5 u
= 17 u
17 u = 51
1 u = 51 ÷ 17 = 3
Number of coins that Tina has
= 8 u
= 8 x 3
= 24
Answer(s): 24