Natalie has 2 times as many coins as Jaslyn. Jaslyn has
67 as many coins as Anna. If the three of them have a total of 50 coins, how many coins does Anna have?
Natalie |
Jaslyn |
Anna |
2x6 |
1x6 |
|
|
6x1 |
7x1 |
12 u |
6 u |
7 u |
The number of coins that Jaslyn has is repeated. Make the number of coins that Jaslyn has the same. LCM of 1 and 6 is 6.
Total number of coins that the three of them have
= 12 u + 6 u + 7 u
= 25 u
25 u = 50
1 u = 50 ÷ 25 = 2
Number of coins that Anna has
= 7 u
= 7 x 2
= 14
Answer(s): 14