Jean has 2 times as many buttons as Natalie. Natalie has
47 as many buttons as Pamela. If the three of them have a total of 114 buttons, how many buttons does Pamela have?
Jean |
Natalie |
Pamela |
2x4 |
1x4 |
|
|
4x1 |
7x1 |
8 u |
4 u |
7 u |
The number of buttons that Natalie has is repeated. Make the number of buttons that Natalie has the same. LCM of 1 and 4 is 4.
Total number of buttons that the three of them have
= 8 u + 4 u + 7 u
= 19 u
19 u = 114
1 u = 114 ÷ 19 = 6
Number of buttons that Pamela has
= 7 u
= 7 x 6
= 42
Answer(s): 42