Abi has 4 times as many pens as Xylia. Xylia has
34 as many pens as Marion. If the three of them have a total of 114 pens, how many pens does Marion have?
Abi |
Xylia |
Marion |
4x3 |
1x3 |
|
|
3x1 |
4x1 |
12 u |
3 u |
4 u |
The number of pens that Xylia has is repeated. Make the number of pens that Xylia has the same. LCM of 1 and 3 is 3.
Total number of pens that the three of them have
= 12 u + 3 u + 4 u
= 19 u
19 u = 114
1 u = 114 ÷ 19 = 6
Number of pens that Marion has
= 4 u
= 4 x 6
= 24
Answer(s): 24