Diana has 2 times as many coins as Irene. Irene has
23 as many coins as Shannon. If the three of them have a total of 54 coins, how many coins does Shannon have?
Diana |
Irene |
Shannon |
2x2 |
1x2 |
|
|
2x1 |
3x1 |
4 u |
2 u |
3 u |
The number of coins that Irene has is repeated. Make the number of coins that Irene has the same. LCM of 1 and 2 is 2.
Total number of coins that the three of them have
= 4 u + 2 u + 3 u
= 9 u
9 u = 54
1 u = 54 ÷ 9 = 6
Number of coins that Shannon has
= 3 u
= 3 x 6
= 18
Answer(s): 18