Kimberly has 30% as many pens as Julie. Julie has 110% as many pens as Lucy. If Julie gives 60 pens to Lucy, both will then have an equal number of pens. Find the average number of pens the three of them have.

Kimberly	Julie	Lucy
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of pens that Kimberly has is repeated.  Make the number of pens that Kimberly has the same. LCM of 10 and 11 is 110.

	Julie	Lucy	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of pens that Julie and Lucy have
= 110 u + 100 u
= 210 u

After Julie gives to Lucy, both of them will have the same number of pens. 

The total number of pens that Julie and Lucy have remains unchanged.

Number of pens that each of them will have
= 210 u ÷ 2
= 105 u

Number of pens that Julie gives to Lucy
= 110 u - 105 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Total number of pens that three of them have
= 210 u + 33 u
= 243 u

Average number of pens that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972

Answer(s): 972