Gem has 30% as many stickers as Min. Min has 110% as many stickers as Cathy. If Min gives 60 stickers to Cathy, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Gem	Min	Cathy
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of stickers that Gem has is repeated.  Make the number of stickers that Gem has the same. LCM of 10 and 11 is 110.

	Min	Cathy	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of stickers that Min and Cathy have
= 110 u + 100 u
= 210 u

After Min gives to Cathy, both of them will have the same number of stickers. 

The total number of stickers that Min and Cathy have remains unchanged.

Number of stickers that each of them will have
= 210 u ÷ 2
= 105 u

Number of stickers that Min gives to Cathy
= 110 u - 105 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Total number of stickers that three of them have
= 210 u + 33 u
= 243 u

Average number of stickers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972

Answer(s): 972