Opal has 30% as many coins as Joelle. Joelle has 110% as many coins as Julie. If Joelle gives 55 coins to Julie, both will then have an equal number of coins. Find the average number of coins the three of them have.
Opal |
Joelle |
Julie |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of coins that Opal has is repeated. Make the number of coins that Opal has the same. LCM of 10 and 11 is 110.
|
Joelle |
Julie |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of coins that Joelle and Julie have
= 110 u + 100 u
= 210 u
After Joelle gives to Julie, both of them will have the same number of coins.
The total number of coins that Joelle and Julie have remains unchanged.
Number of coins that each of them will have
= 210 u ÷ 2
= 105 u
Number of coins that Joelle gives to Julie
= 110 u - 105 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Total number of coins that three of them have
= 210 u + 33 u
= 243 u
Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 11
= 891
Answer(s): 891