Rachel has 30% as many beads as Winnie. Winnie has 140% as many beads as Min. If Winnie gives 40 beads to Min, both will then have an equal number of beads. Find the average number of beads the three of them have.
Rachel |
Winnie |
Min |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of beads that Rachel has is repeated. Make the number of beads that Rachel has the same. LCM of 10 and 7 is 70.
|
Winnie |
Min |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of beads that Winnie and Min have
= 70 u + 50 u
= 120 u
After Winnie gives to Min, both of them will have the same number of beads.
The total number of beads that Winnie and Min have remains unchanged.
Number of beads that each of them will have
= 120 u ÷ 2
= 60 u
Number of beads that Winnie gives to Min
= 70 u - 60 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Total number of beads that three of them have
= 120 u + 21 u
= 141 u
Average number of beads that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 4
= 188
Answer(s): 188