Hilda has 30% as many coins as Kimberly. Kimberly has 110% as many coins as Raeann. If Kimberly gives 55 coins to Raeann, both will then have an equal number of coins. Find the average number of coins the three of them have.

Hilda	Kimberly	Raeann
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of coins that Hilda has is repeated.  Make the number of coins that Hilda has the same. LCM of 10 and 11 is 110.

	Kimberly	Raeann	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of coins that Kimberly and Raeann have
= 110 u + 100 u
= 210 u

After Kimberly gives to Raeann, both of them will have the same number of coins. 

The total number of coins that Kimberly and Raeann have remains unchanged.

Number of coins that each of them will have
= 210 u ÷ 2
= 105 u

Number of coins that Kimberly gives to Raeann
= 110 u - 105 u
= 5 u

5 u = 55

1 u = 55 ÷ 5 = 11

Total number of coins that three of them have
= 210 u + 33 u
= 243 u

Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 11
= 891

Answer(s): 891