Joelle has 25% as many marbles as Penelope. Penelope has 130% as many marbles as Yen. If Penelope gives 48 marbles to Yen, both will then have an equal number of marbles. Find the average number of marbles the three of them have.
Joelle |
Penelope |
Yen |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of marbles that Joelle has is repeated. Make the number of marbles that Joelle has the same. LCM of 4 and 13 is 52.
|
Penelope |
Yen |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of marbles that Penelope and Yen have
= 52 u + 40 u
= 92 u
After Penelope gives to Yen, both of them will have the same number of marbles.
The total number of marbles that Penelope and Yen have remains unchanged.
Number of marbles that each of them will have
= 92 u ÷ 2
= 46 u
Number of marbles that Penelope gives to Yen
= 52 u - 46 u
= 6 u
6 u = 48
1 u = 48 ÷ 6 = 8
Total number of marbles that three of them have
= 92 u + 13 u
= 105 u
Average number of marbles that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 8
= 280
Answer(s): 280