Betty has 30% as many stickers as Joelle. Joelle has 110% as many stickers as Tiffany. If Joelle gives 20 stickers to Tiffany, both will then have an equal number of stickers. Find the average number of stickers the three of them have.
Betty |
Joelle |
Tiffany |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of stickers that Betty has is repeated. Make the number of stickers that Betty has the same. LCM of 10 and 11 is 110.
|
Joelle |
Tiffany |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of stickers that Joelle and Tiffany have
= 110 u + 100 u
= 210 u
After Joelle gives to Tiffany, both of them will have the same number of stickers.
The total number of stickers that Joelle and Tiffany have remains unchanged.
Number of stickers that each of them will have
= 210 u ÷ 2
= 105 u
Number of stickers that Joelle gives to Tiffany
= 110 u - 105 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Total number of stickers that three of them have
= 210 u + 33 u
= 243 u
Average number of stickers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 4
= 324
Answer(s): 324