Jaslyn has 30% as many stickers as Min. Min has 140% as many stickers as Cathy. If Min gives 100 stickers to Cathy, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Jaslyn	Min	Cathy
3x7	10x7
	7x10	5x10
21 u	70 u	50 u

30% = ³⁰₁₀₀ = ³₁₀
140% = ¹⁴⁰₁₀₀= ⁷₅

The number of stickers that Jaslyn has is repeated.  Make the number of stickers that Jaslyn has the same. LCM of 10 and 7 is 70.

	Min	Cathy	Total
Before	70 u	50 u	120 u
Change	- 10 u	+ 10 u
After	60 u	60 u	120 u

Total number of stickers that Min and Cathy have
= 70 u + 50 u
= 120 u

After Min gives to Cathy, both of them will have the same number of stickers. 

The total number of stickers that Min and Cathy have remains unchanged.

Number of stickers that each of them will have
= 120 u ÷ 2
= 60 u

Number of stickers that Min gives to Cathy
= 70 u - 60 u
= 10 u

10 u = 100

1 u = 100 ÷ 10 = 10

Total number of stickers that three of them have
= 120 u + 21 u
= 141 u

Average number of stickers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 10
= 470

Answer(s): 470