Jen has 25% as many pens as Hilda. Hilda has 130% as many pens as Xandra. If Hilda gives 30 pens to Xandra, both will then have an equal number of pens. Find the average number of pens the three of them have.
Jen |
Hilda |
Xandra |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of pens that Jen has is repeated. Make the number of pens that Jen has the same. LCM of 4 and 13 is 52.
|
Hilda |
Xandra |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of pens that Hilda and Xandra have
= 52 u + 40 u
= 92 u
After Hilda gives to Xandra, both of them will have the same number of pens.
The total number of pens that Hilda and Xandra have remains unchanged.
Number of pens that each of them will have
= 92 u ÷ 2
= 46 u
Number of pens that Hilda gives to Xandra
= 52 u - 46 u
= 6 u
6 u = 30
1 u = 30 ÷ 6 = 5
Total number of pens that three of them have
= 92 u + 13 u
= 105 u
Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 5
= 175
Answer(s): 175